Easy Steps to Draw A Hyperbola using Focus Directrix Method - Engg Curves - Engg Drawing

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This EzEd videos explains how to construct a HYPERBOLA using FOCUS DIRECTRIX METHOD when distance between the focus and DIRECTRIX is 50 mm and ECCENTRICITY is 3 by 2. Draw a TANGENT and NORMAL at any point on the hyperbola.

Solved Problem from University Questions

Instruments used are
Scale
French Curve
Geometric Compass
Protractor

We at EzEd aim to make education easy.

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Very ausome direct teaching no bakwaas👍

shlokmantri
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awesome explnation sir thank uh so much sir 😇😇

venuyadav
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Very Useful For Last Minute Revisions 👌

kushalsharma
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Draw a hyperbola when the distance of its focus from directrix is 65 mm
and eccentricity is 4/3. Draw a tangent and normal to the curve at a distance
of 35 mm from directrix.
Try this one

itsme-upuz
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As of now I'm sitting in the engineering drawing lab at IIT kharagpur watching this cuz the TA's don't give a fuck

MMM hall just in case another kgpian is watching

shauryathakur
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Construct Hyperbola Curve When Distance of Focus from Directrix is 45 mm and Eccentricity 2/1.

jenil
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Draw a conic curve whose distance of focus from directrix is 55 mm and eccentricity=1.5.Also draw tangent and normal at a distance of 50 mm from the fixed line

hackwithfact
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.Draw a conic curve when the distance of the focus from the vertex is 45 mm and
the eccentricity e = 3/2. Name the curv

komalthakor
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Draw a hyperbola when the distance its focus and directrix is
50mm and eccentricity is 3/2.

satvika
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Thanks very much…please what app are you using to teach?

tega
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Please make a video to draw hyperbola by vertices focus method

Vertices and focus are given

abdulmajidghaniani
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Abe parabola aur hyperbola ek hi jaisa tune nikala hai😂

ShivrajSawant-whxc
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wrong video this will make an ellipse not a hyperbola because V is marked wrong

RAZIK-su