Find the 5 digit Number abcde where abc divisible by 4 bcd by 5 and cde by 3 Challenge

[vaibhavshekhar]

That's how I did sir...
ABC is divided by 4. So last 2 digit that is BC is gonna be divisible by 4. So, A24 is the number.
Now BCD is divisible by 5. So, last should be 5. Number will be A245.
CDE is divisible by 3. So, sum of digits should be divisible by 3. So A2453
REST IS 1. SO 12453.

[divyampancholi]

Thanks you sir for wonderful explanation

[sanmiguel]

I keep watching it over & over and still dont make sense. Abc 1+2+4 = 7 and first rule is divisible by 4