Continuity & differentiability | Part 4 | JEE Advanced Symposium | ISI | CMI | 45+ selected problems

Continuity & differentiability | Part 4 | JEE Advanced Symposium | ISI | CMI | 45+ selected problems

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[kushalagarwal]

Sir these videos are very helpful in boosting my confidence in jee advance
Thank u sir.

[akshays]

sir at 26:18 can we not directly say that since f(x) = sin-1(sin 2theta) has two points of non differentiability according to the graph and at those points (2 theta = +-pi/2) we can find corresponding values of x, we still get the answer

[akshays]

sir at 1:04:25 my approach was that according to the question f'(x) is even function so f(x) has to be odd. now if f(x) is assumed to be even then it still has to be an odd function right so f(x) + f(-x) has to be zero. is this the right approach

[maneetkaur]

Sir what is the source of your questions in jee advanced compendium videos?