A force acts on a 3 g particle in such a way that the position of the particle as a function of time

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A force acts on a 3 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t^2 〖+t〗^3, where x is in metres and t is in seconds. The work done during the first 4 second is
(a) 490 mJ (b) 450 mJ (c) 576 mJ (d) 530 mJ.
(1998)

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