Gauss’s Law & its application -III

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  1. Electromagnetic theory
  2. Gauss's law and its application-III
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Комментарии
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the way professor uses (r) to denote vectors is the main cause of this confusion, try replacing (a) with (r) then integrate D.ds for top and bottom surface. Also, Z = h/2 for top surface.

Knowledge_is_a_blessing
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Formula of divergence for cylinderical co ordinates is
1/r(d(rf)/dr)+ 1/rdf/dphi(phi direction) + df/dz
in first term multiply r with function and than partial differentiate

KEERAMVs
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sir in top and bottom flux calculations at 20:55 instead of (( h)) there will ((h/2)).

sakshamsahdev
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Del.d =3 by direct aplication of the formula for the given d and del for cylindrical surface

muralidhar
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at 26:58 why did you say that we cannot apply gauss's law here.. Please state the reasons Sir...

sahilanower
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well "half a loaf is better than nothing" thanks sir for helping …………...

sakshamsahdev