In the third question are we sure that the factor of a quardratic equation is automatically the root?
ashubham
How does the trickery presented at 22:00 that you aren't supposed to assume p and q to be integers apply (turns out you should have used deicimals), but the same logic doesn't apply when looking for divisible numbers of 110 as seen at 31:05? 110 can be divided by all real numbers, you may just get decimals or negative numbers in some case. Why are you supposed to assume it's only talking about integers that represent factors of 110? The GMAT wants it both ways.
koolman
in question 2, 9 is also a factor of 108
Anjalibansalart
My highschool never taught me the sum or product of roots so I just learnt that in this video 😅😅
PeanutBreathing
Question for #2.
Not sure how he got p = 27*k from the first statement "p is divisible by all the factors of 27"...
( p = 27*k is rather interpreted as "p is divisible by 27", not the factors of 27)
If p is divisible by all the factors of 27 - which implies all the factors of 27 are 1, 3, 9, and 27 - hence satisfies that p = 1*a, p= 3*b, p= 9*c, p= 27*d, where a, b, c, and d are all integers.
Am I getting wrong here?
Thus, both statements put together gives two possible answers 9 and 54 - thus I thought E was correct.
Anybody can help here?
sunhoma
I have a doubt in question 4.
Actually the question is, Is x>y ....
And the assumptions are (x+1) <2 so according to this assumption the values are only-2, -1 and 0 . There will be no -3 because if we add -3 with 1 there modules will be 2 thats equals to 2 and the assumption given here is less than 2 as the same way the assumption 2 comes here with tge possibilities of -13, -3 . So here the values of x is more greater than the values of y. So My conclusion for this problem gonna be Option C.
alijinna
Give these questions to a CAT aspirant and they'll laugh in your face
