Minimum Moves to Equal Array Elements | Leetcode Python Solution | Python

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Minimum Moves to Equal Array Elements | Leetcode Python Solution | Python
In this programming series, we will be going over a complete introduction to the design and implementation of algorithm using Python. It will allow us to perform quick execution of code within limited time frame. We will be focussing on both time and space complexity to enhance our solution to efficient one.

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PythonGuruji

can you please make a playlist on basics on data structures and algorithms and hints and tricks to attempt leetcode questions

hannanbutt

very nice way of explaining the approach

ankitnishad

Hello, in method one instead of two for loops, can we do something like this?
while(min(nums)!=max(nums)):
nums.sort()
nums=[i+1 for i in range(len(nums)-1)]
c=c+1
return(c)

vishaks

great explanation but 2 and 3 can be reduced by 1 in a single move and then we are left with : [ 1 1 2 ] now in one more move it will turn to [ 1 1 1] i.e this happens in 2 moves, so how is the decrement logic apt ?

sans.creates

Kaafi acha video tha bhaiya, bas ek baat batadijiye ki aise approach khud apne dimag se kaise develop karein, kyunki test me develop nhi kar pate aise badhiya approaches 😓😓😓

utkarshchauhan

No one Really No one in Youtube Explain like this all are just telling the solution they don't give the logic (relative distancing ) behind it.

VikasMishra-mk

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