NPTEL Programming in Java Week 12 Programming Assignment Solution Augut 2024 | IIT Kharagpur

Welcome to our detailed walkthrough of the "NPTEL Programming in Java Week 12 Assignment Solution for July 2024," presented by IIT Kharagpur. This video is tailored for students and professionals eager to deepen their understanding of Java programming and looking to excel in their coursework.

In this tutorial, we will guide you through the solutions to the Week 12 assignment of the NPTEL course on Programming in Java. Whether you're a beginner or looking to refresh your knowledge, this video will provide you with a comprehensive breakdown of key concepts and practical applications taught by leading experts from IIT Kharagpur.

We'll start with an overview of the assignment, followed by step-by-step solutions and explanations. Additionally, we'll share useful tips and insights to help you grasp complex Java programming concepts and apply them effectively in real-world scenarios.

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[CodingOClock]

Programming Assignment
Answer 1:
try {
for (int i = 0; i < length; i++) {
name[i] = sc.nextInt();
sum += name[i];
}
System.out.println(sum);
} catch (InputMismatchException e) {
System.out.println("You entered bad data.");
}

Answer 2:
char original[][]= new char[5][5];
// Input 2D Array using Scanner Class and check data validity
for(int line=0;line<5; line++){
String input = sc.nextLine();
char seq[] = input.toCharArray();
if(seq.length==5){
for(int i=0;i<5;i++){
if(seq[i]=='0' || seq[i]=='1'){
original[line][i]=seq[i];
if(line==4 && i==4)
flipflop(original);
}
else{
System.out.print("Only 0 and 1 supported.");
break;
}
}
}else{
System.out.print("Invalid length");
break;
}
}
}
static void flipflop(char[][] flip){
// Flip-Flop Operation
for(int i=0; i<5;i++){
for(int j=0; j<5;j++){
if(flip[i][j]=='1')
flip[i][j]='0';
else
flip[i][j]='1';
}
}
// Output the 2D FlipFlopped Array
for(int i=0; i<5;i++){
for(int j=0; j<5;j++){
System.out.print(flip[i][j]);
}
System.out.println();
}

Answer 3:
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++) {
System.out.print("*");
}
for (int j = 1; j <= 2 * (n - i); j++) {
System.out.print(" ");
}
for (int j = 1; j <= i; j++) {
System.out.print("*");
}
System.out.println();
}

// Print the lower half of the butterfly
for (int i = n; i >= 1; i--) {
for (int j = 1; j <= i; j++) {
System.out.print("*");
}
for (int j = 1; j <= 2 * (n - i); j++) {
System.out.print(" ");
}
for (int j = 1; j <= i; j++) {
System.out.print("*");
}
System.out.println();
}

Answer 4:
public boolean solveSudoku(int[][] board) {
for (int row = 0; row < 9; row++) {
for (int col = 0; col < 9; col++) {
if (board[row][col] == 0) {
for (int num = 1; num <= 9; num++) {
if (isSafe(board, row, col, num)) {
board[row][col] = num;
if (solveSudoku(board)) {
return true;
} else {
board[row][col] = 0;
}
}
}
return false;
}
}
}
return true;
}

// Method to check if it's safe to place a number
public boolean isSafe(int[][] board, int row, int col, int num) {
for (int x = 0; x < 9; x++) {
if (board[row][x] == num || board[x][col] == num ||
board[row - row % 3 + x / 3][col - col % 3 + x % 3] == num) {
return false;
}
}
return true;
}

// Method to print the board without spaces
public void printBoard(int[][] board) {
for (int row = 0; row < 9; row++) {
for (int col = 0; col < 9; col++) {

}
System.out.println();
}
}

[tusharsherwal]

Thank you soo much brother this was very helpful for me

[adhithanr]

There are 5 programming assignment but you have given answer for only 4, plz give 5th code also bro ❤