1-2+3-4 + 5-6 +7 = 1/4

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To approach the expression using calculus, we can treat it as a finite sum of a sequence.

Define the function:

f(n) = \sum_{k=1}^{n} (-1)^{k+1} k

This means alternates the signs of the integers from 1 to .

1. For odd, like :



f(7) = 1 - 2 + 3 - 4 + 5 - 6 + 7

2. We can observe that the pairs cancel out:

The sum of pairs (like ) yields

aninditabanerjee
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Im confused y do u need to apply calculus when that was not an f(x) (calculus) question it was just a simple math right

afsalali
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Haven’t seen you solve one chemistry problem??

SixOhFive
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im 8yo
and dont know what know what this is

MR.Biswas-Computer-Class
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1/4? huh?

every number never giving you any fraction from total
1-2 = -1
1-2+3 = 2
1-2+3-4= -2

even if we talk about infinite series of number, you will never get the sum of series will be fraction

Balabala-iqne