Implicit differentiation shortcut (calculus 3)

We will compare the implicit differentiation method from Calculus 1 and the "shortcut" from Calculus 3. We will find dy/dx of x^3+xy^2=sin(y). Subscribe to @bprpcalculusbasics for more calculus tutorials.

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[yourlilbrudder]

My Calc BC teacher taught the "multi way". Makes it so much easier.

[tigerinthejungle_]

I'm in Calc 2 right now and my teacher already said us to use this formula even though it was not there in the material and said that we will understand it later. Now I know why

[jeisondurango]

You omitted the 2 from the second term in your thumbnail

[itsphoenixingtime]

i always wanted a formula for implicit differentiation and I found it! When I tried it on all my 12th grade problems it felt amazing that it worked out the same way.

[FredFigglehornOfficial]

could we get more videos like this where further calc methods are useful for stuff in calc I 🙏

[AubreyForever]

How do you prove the Calc 3 way of doing this problem. I like it but not sure the proof why these partial derivatives work.

[glorymanheretosleep]

This is what I am talking about. I thought you only made algebra videos, nice to see you can do more complicated problems.

[jomariraphaellmangahas]

When will you introduced vector calculus?

[parthhooda]

I was expecting it to be purely in terms of x because for me just calculation the derivative was pretty easy