Class 12 Physics NCERT Solution | Q2.16 Chapter 2 | Electric Potential & Capacitance

2.16 (a) Show that the normal component of electrostatic field has a
discontinuity from one side of a charged surface to another
given by
(E2-E1)= σn^/ε
where ˆn is a unit vector normal to the surface at a point and
σ is the surface charge density at that point. (The direction of
ˆn is from side 1 to side 2.) Hence show that just outside a
conductor, the electric field is σ ˆn /ε0.
(b) Show that the tangential component of electrostatic field is
continuous from one side of a charged surface to another. [Hint:
For (a), use Gauss’s law. For, (b) use the fact that work done by
electrostatic field on a closed loop is zero.]

[tanishqsangwan]

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[thedarklord]

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Mast samjhaya
Thanks 🙂

[shraddha]

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[indianbhai]

Sir vo jo aapne E.dl liya tha usme E ke place pe E1-E2 kyo liya