A Nice Algebra Problem From Sweden | Algebra Problem Solving | Olympiad Mathematics

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A Nice Algebra Problem From Sweden | Algebra Problem Solving | Olympiad Mathematics

Topics Covered :-
1. Olympiad Mathematics
2. Algebra Problem Solving
3. Math Olympiad Problem

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...1/a+1/b+1/c=3 or (ab+bc+ca)/abc=3.reversing, we get abc/(ab+bc+ca)=1/3.thus shortened.

prabhudasmandal
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You can just write a, b, and c in the form of log base 8, 27, and 125 of 30, respectively, then input it into 1/(1/a+1/b+1/c).

keenan-
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Hint: Let the constant term be K and break 30 into (2×5×3)

You will get the answer, before watching the video try it

KM-omhm
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3a equals 3b equals 3c a equals b equals c now put the value of a equals 1 b equals 1 c equals 1 answer would be 1by 3

NishantKumar-yhuw
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Can you solve this olymbiade:
X^3+X^2×Y=9 and Y^3+Y^2×X= 25
X, Y positives numbers
Find X+Y

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