Equations of Motion : Derivation of Third Equation of Motion - Motion | Class 9 Physics

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✅ In this video,

✔️ Class: 9
✔️ Subject: Physics
✔️ Chapter: Motion
✔️ Topic Name: Equations of Motion : Derivation of Third Equation of Motion
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00:00 Introduction
0:17 Equations of Motion : Derivation of Third Equation of Motion - Motion
12:14 Websites Overview
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Points covered in this video:-

Third equation of motion It gives the velocity acquired by a body in travelling a distance s.
Derivation:
3rd equation of motion can be obtained by eliminating + between the first two equations of motion. .

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Previous Video:
Equations of Motion Derivation Method 2 (Part-1) | Motion
Next Video: NCERT Questions (Part-1) | Motion

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explanation
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[maxu_]

Actually mere heesab s ye bhut hard tarike s derive kiya hai..simple tarika aese hai:-
Hme pta hai v=s/t
Also v=v+u/2
So we can say that s/t=v+u/2
Now solving the above equation we get
S=t×(v+u/2)
[ t= v-u/a ] from first equation of motion
Putting the value of t we get
S= (v-u/a)(v+u/2)
S=v^2-u^2/2a
2as=v^2-u^2
Hence proved