Finding Trigonometric Function Values Given One Trig Value in a Right Triangle, Ex 1

[zakartaz]

Dude, thank you so much! You are really the best!

[iversonsung]

9 years later... *Helps high school student*
What was so hard about this? 😂

[Guhig]

Thanks man, just got back to school and needed a quick refresher.

[Kayla-xotz]

God bless you. I learned more in one of your videos than 2 weeks of Math 141.

[androcci]

THANK YOU!!! and i haven't yet started to watch the video yet but i know is going to be a good guide and i will learn lol. =)

[Smiling_Tears]

It depends on what quadrant we're working in. In the first quadrant, all the trig functions are positive. in the second, sine and cosecant are positive. In the third, tangent and cotangent are positive. and in the fourth quadrant, cosine and secant are positive.

[THERaynaKay]

I love how you're left-handed, dude! :D

[someoneelse]

Thank you this really helped my homework ;)

[randomperson]

i forget all the stuff i learned about radicals/square roots, but couldn't you take the square root aka 10.9 and use that as an answer for the ratio? or would that be incorrect?

[davidreadiii]

How would you find the value of theta when only given the trig function and it's value???

[ssogarra]

what if you have cosecant 0(beta) = 5, and your expected to find the third side and then find the other five trigonometric functions of 0(beta). Using the Pythagorean Theorem, help please.

[ambsxxrawr]

Aren't cscx, secx and cotx supposed to be negative? I'm confused now...

[lilguava]

This is good but what if all they give you is the degrees?

[kieraslater]

At about 4:10, he shows that 12/root 119 is the complete answer for csc. However, this is incorrect. You cannot have a root in the denominator. In order to cancel out the root in the denominator, you need to multiply the fraction by root 119/root 119, which is another form of 1. Now, you have 12/root 119 X root 119/root 119. The roots in the denominator cancel out and become just 119. The answer to this is csc (x)=12•root 119/12.