Pair of Array Elements Generate Required SUM | Logical Programming in C | Naresh IT

Pair of Array Elements Generate Required SUM | Logical Programming in C | Naresh IT

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[swacharahman]

Sir thousands of thanks.... I had almost waste 2/3 hours to find a good video where i can get clear concept and in your video you have provide it...thanks sir..love from Bangladesh

[learningislife]

I m big fan sir
Your teaching mind blowing ..kuch bhe samaj nahi aata to main aap ki video dhek leta hu aur mere pure dout clear ho jate hai

[himanshupathak]

Thanks a lot sir
Your teaching style is brilliant

[khandkerassikuzzaman]

If
sum = 10
n = 8
input data or array elements are : {3, 3, 3, 3, 3, 3, 3, 7}
Then
output will be:
(3, 7)
(3, 7)
(3, 7)
(3, 7)
(3, 7)
(3, 7)
(3, 7)
Here, 6 times same pair repeats.

[saddamahmad]

thank you very much sir for this video

[aniruddhapaul]

Thank u sir. Sir please make sorting cocepts(different sorting technique) videos.It will be very helpful for us.

[MUKESHJCSE_]

Sir required sum=10 to add 7+1+2 is also 10 how to find it sir

[swapnalipatil]

Sir how many loops required for if our required sum is obtain by adding 4 elements of array....

[muppinalakshmansaia]

hello sir, im following yours lectures only to learn programming.but i want to know how to print sum of adjacent numbers in c.could u plz help me to solve that type of programs and i want to know the logic

[biswajitghosh]

Sir how I find coprime number to arrays
Two or more number

[KAGANASHIVAJYOTHI-kf]

Why we use the temporary value in programming

[satvikkhare]

And then interviewer will ask to optimise it coz interviewers hate O(N^2) complexity, and if you can't tell that you will be rejected, we have to use hash map over here

[kirantak]

Your teaching mind blowing.
sir this program is correct or not.


pair of array elements generate required diffrence program


#include <iostream>

using namespace std;

int isprime(int val)
{
if(val>=2)
{
for(int i=2;i<val;i++)
{
if(val%i==0)
return 0;
}
return 1;
}
else
return 0;
}

int main()
{
int n;

cout<<"entr size of array";
cin>>n;
int a[n];
cout<<"enter "<<n<<" number"<<endl;
for(int d=0;d<n;d++)
{

cin>>a[d];
} //int a[5]={1, 5, 3, 4, 2};
// int a[n];
//int diff=3;
//int diff1=2;
int count=0;
int temp;
if(n<=50)
{
cout<<"pairs are follows :"<<endl;
for(int i=0;i<n;i++)
{
for(int j=0;j<n;j++)
{

if(a[j]!=a[i] && a[j]<a[i] )
{
if(isprime(a[i]-a[j])==1)
{
count++;
cout << "("<<a[i]<<"-"<<a[j]<<")" << endl;
}


}

}
}
}
return 0;
}