Coursera: Assignment 3.3 Python for everybody assignment solution//#Python assignment solution

# Coursera :-
#Programing for everybody
# Python

CHAPTER :-
QUIZ
QUESTION WITH ANSWER
👇Chapter :- 1 Quiz 👇
👇Chapter :- 2 Quiz 👇
👇Chapter :- 3Quiz 👇

👇Chapter :- 4 Quiz 👇

👇👇Assignment :- 2.2👇👇

👇👇Assignment :- 2.3👇👇

👇👇Assignment :- 3.2👇👇

👇👇Assignment :- 3.3👇👇

👇👇Assignment :- 4.6👇👇

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👇👇Programing run code 👇👇

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Python is a general purpose and high level programming language. You can use Python for developing desktop GUI applications, websites and web applications. Also, Python, as a high level programming language, allows you to focus on core functionality of the application by taking care of common programming tasks
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THANKING YOU 😘

[cankrkurdozdemir]

Updated with simple commands to include
- skipping error for non floats,
- not quitting but going to start when non float of out of range numbers entered,
- asking if you want to calculate another grade or quit.

def grade_calculator():
while True:
score = input("Please Enter Score between 0.0 and 1.0: ")
try:
if float(score) > 1 or float(score) < 0:
print('out of range')
continue
elif float(score) < .6:
grade = 'F'
break
elif .7 > float(score) >= .6:
grade = 'D'
break
elif .8 > float(score) >= .7:
grade = 'C'
break
elif .9 > float(score) >= .8:
grade = 'B'
break
else:
grade = 'A'
break
except:
print('please enter a valid floating number')
continue
print(grade)


grade_calculator()

while True:
repeating = input('would you like to enter another score (y or n) ?')
if repeating != 'y' and repeating != "n":
print("please enter y or n")
continue
elif repeating == "n":
print('program ended')
quit()
else:
grade_calculator()

[darshanawakalkar]

Thnxx a lot bro.. After lot of trials this code finally work without any errors..

[avuladurgaprasad]

inp = input("Choose a score between 0.0 and 1.0")

score = float(inp)

 

if score >= 0.0 and score < 0.6:

   print('F')  

 

 

elif score >= 0.6 and score < 0.7:

   print ('D')  

 

elif score >= 0.7 and score < 0.8:

   print ('C')  

 

elif score >= 0.8 and score < 0.9:

   print ('B')  

 

elif score >= 0.9 and score <= 1.0:

2 / 2

   print( 'A')  

 

else:

   print('Error: input not within range')

[rishabhparmar]

Guys, if you're getting " Check code " even if the syntax and the program is right.. it's because the desired output is 'B' grade.. so during input if you enter ' 0.8 ' it will run successfully