Array Pair Sum Divisibility Problem | 🧑‍💻 C++, Java, Python | Hash Map | Most Optimal Solution | GFG

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Hi everyone, welcome to my channel where I upload the video solutions to the "Problem of the day" that is asked daily on GeeksforGeeks. Today's problem is "Array Pair Sum Divisibility Problem" which is a medium level question.

In this video, I will explain an optimised Hash map solution to solve this problem which is both time efficient, O(N), where N is the size of the Matrix and space efficient, O(N).

00:00 Introduction to the problem
01:45 Understanding the problem
02:25 Framing the approach to solve the problem
10:24 Going through the code

I hope you enjoyed this video and learned something new. If you did, please give it a thumbs up 👍 and share it with your friends who are also interested in coding. And don't forget to subscribe to my channel and hit the bell icon 🔔 to get notified whenever I upload a new video. Thank you for watching and see you in the next one! 😊

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day by day your way of delivery the approach of a problem is improved. great explanation

ksvijayan
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For the first element 9, it increments the frequency of 3 in the map (mp[3]++).
For the second element 5, it increments the frequency of 1 in the map (mp[1]++).
For the third element 7, it increments the frequency of 5 in the map (mp[5]++).
For the fourth element 3, it decrements the frequency of 3 in the map (mp[3]--).
Now, let's check the final state of the map:

mp[1] has a frequency of 1 (from the second element).
mp[3] has a frequency of 0 (from the first and fourth elements, but decremented once).
mp[5] has a frequency of 1 (from the third element).
According to the logic in the code, it checks if all frequencies in the map are zero before returning true. In this case, the frequencies are not all zero (mp[1] and mp[5] are non-zero), so the function should return false.

YT_Fresher
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