Projectile under an angular projection||kinematics||Unit 2||STD 11 Physics||Tamil

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Sir very thanks its very easy to understand after seeing your videos I got full marks in physics ❤❤ thankyou very much

DossS-po
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I understand very well
TQ so much ....sir,

manimoshi
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Sir now only i watching this for public after watching your important question

yogesarun
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Easy to understand sir...continue ur...job..
👌👌👌👌

Tamil_
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Very neat and clear explanation sir. I am a teacher This year I am handling class 11. This is my first year experience for class11. For my teaching i am using your videos for reference

RevathiPagavathi
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Onga channel ippo than paakuren i admired by u sir😍

muthuram
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Sir pls don't miss the concept. Ella topic um video potuka

vijaykumart
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Pls neet & jee point la yu teach panuga

vaishnaviswaminathan
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Sir, Projectile in horizontal projection podalaya?

ddshorts
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No words to tell some thing about your teaching. Always you are the best sir🤩😇

jeemagima
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Well explained sir .but one thing i noticed that during 8.37 you said that Uy=0 that means Uy=Usin(teta) will be zero but u said that Ux=Usin(teta).why sir? I thing Ux= Ucos(teta) is it right or wrong sir?

SGOPI-qluq
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Sir font size increase pannunga sir please

jaferhussain
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Very clear explanation sir ...
Thank you so much sir...

duraipoongodi
welcome to shbcf.ru