Evaluating the Definite Integral of |cosx| from 0 to pi

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Evaluating the Definite Integral of |cosx| from 0 to pi
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Thanks a million:)
I dunno how I'd finish off my math worksheets without this!!

aparna
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This question has been asked in one of our national level competitive exam IIT JAM. Thanks sir! From India 🇮🇳

ashvaryashankar
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Hey buddy ....thks for this i was searching this answer on google ....but you know u r video was the only video which is recommended on google for this question🥳🥳❤💯

meraroast
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could you double integrate this/ when instead of x we have x+y and x and y are both from 0 to pi

tommoritz
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Use the King's property
Substitute π-x instead of x
Integral = |cosx| remains unchanged
So, I= 2* Integral (0 to π/2) of
|cosx| dx
cosx > 0 in x€(0, π/2)
I= 2*(sin(π/2)-0)=2
I= 2

pavitrajeemath
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where'd the π/2 come from?

0:46

Parps
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Plz make more video of this type of que

mahnazquamar
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What's the answer of integration upper limit 2pi and lower limit 0 mod cosx into dx =4

nancydebbarma
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And if we put 2pi instead of pi so what would be the ans?

iqrazahid
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Sir,
Which is wrong explanation.

marul