Java Program to Find the Count of Occurrences of Each Character in a String

Write a Java Program to Find the Count of Occurrences of Each Character in a String. Well, if you are appearing for any IT company interview this is the most expected question in your Technical round of interviews. Now, you need not fear for Technical rounds, " .because we are bringing you the entire series of "Frequently asked Programming Questi".Subscribe to our channel for more videos and Crack your Interviews successfully!

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[cid]

map in c++ very much easier than java code :

map<char, int> cnt;
string x = "AAXAA";

for(char c: x) {
cnt[c]++;
}

cout << cnt['A'] << endl;

[soudiptadutta]

I think we should use the function map.getOrDefault here. By using that we don't have to write more lines of code. Here is the complete program.

public class CountEachCharacterInString {
public static void main(String[] args) {
String str= "GinaGiniProtijayi";

fix(str);
}

private static void fix(String a) {
Map<Character, Integer> map = new LinkedHashMap<>();
List<Character> list = new ArrayList<>();
for( char ch : a.toCharArray()) {
map.put(ch, map.getOrDefault(ch, 0) + 1 );

}//for
map.forEach((k, v) -> System.out.println(k +" : " + v));

}


}//end1

[moiyetresorkonan]

thank you very much, i was looking for something like this and you really good deed explain it

[ishashri]

thanks for the video, you should check for and change the string to upper or lower case as well when removing the spaces

[UdayKumar-olyz]

if input= AAABBACCBB then output=3A2BA2C2B
what is the code for the above one

[veereshhiremath]

Madam you did great
But by using for loop is very is to understand for non cs background and freshers so instead of dis make new one by using for loop
Thank you mam

[shaantalk]

use this solution....it uses collections to its fullest....


import java.awt.AWTException;

public class A {

public static void main(String[] args) {
String str = "helloworld";
List<String> myList = Arrays.asList(str.split(""));
Set<String> setx = new HashSet<String>(myList);
for(Object obj : setx) {
System.out.println(obj+" found in "+Collections.frequency(myList, obj));
}
}
}

[Shiroyashasama]

at 6:20 you said youll show us how that looks in the main functions but you ventured off to something else.

[v.r.]

sorry but why you replacing character which is checked, you unnecessarily increase time complexity and making your code very harder !! please make it simpler !!

[shrikantkoli]

If this explanation on a system, it would be better to understand.

[akashagarwal]

@talentspirit can you explain countChar function with an example

[k_thai_edits]

Mam can you please figure me out how to make replace function without using array???

[dhruvsingh]

Can we use for loop for that
Please reply

[farazmohammed]

sach batu..?? kuch samaj nahi aaya..😕🙁

[lovishbhateja]

u should have shown the exact code too.

[ankitshrivastava]

use the HashMap and get rid of all the complex logic.

[Sanjeevkumar-clnl]

The code doesn't work
package testCases;

public class OccurenceOfEachCharacter {

public static void occurence(String str, char ch) {
int count = 0;
while (str.indexOf(ch) != -1) {
count++;
str =

}
}

public static void main(String args[]) {
String str = "mycode";
while (str.length() > 0) {
char ch = str.charAt(0);
occurence(str, ch);
System.out.println(str);

str = str.replace("" + ch, "");
}
}
}

[saniyamansuri]

how to count occurance of char in a string without using any loop

[devendramalviya]

ma'am one more solution

public class Test {

public static void main(String[] args) {
String ss = "you are beautiful";

String s = ss.replace(" ", ""); //replacing the space
for(int i =0; i<s.length();i++)
{
int count =0;
for(int j=0; j<s.length() ; j++)
{
if(j<i && s.charAt(i)==s.charAt(j)){
break;
}

if(s.charAt(i)==s.charAt(j)){
count++;
}
if(j==s.length()-1){
= "+count);
}
} //end of j loop

} //end of i loop
} //end of main method

} //end of class

[huvannacn]

1)write a java program to find the count of occurrences of each character in string but 

Example: I am ram

  A=2; time 

  B=0;

  C=0;

  .

  .

  .

  Z=0; times 

Pls explain