First shifting theorem: Laplace transforms

preview_player
Показать описание
How to apply the first shifting theorem of Laplace transforms. A basic example is discussed and solved.
Рекомендации по теме
Комментарии
Автор

Thank you so much, I always appreciate when people go out of their way to help others :)

DutchKid
Автор

I'll also post a basic one where you take the inverse transform via FST in a few days. Always appreciate your comments!

DrChrisTisdell
Автор

Yes, some tables have it this way also (but not the tables from my classes).

DrChrisTisdell
Автор

Thanks! I am "suffering for my art"! :-)

DrChrisTisdell
Автор

so basically if you know the Laplace Transform of a function f(t), which is L{ f(t) }, then you can get L{ e^(at) * f(t) }.

if L{ f(t) } = F(s)
then L{ e^(at) * f(t) } = F(s - a)

hasaniqbal
Автор

Thanks for this short "how-to" video.

Am I correct in thinking that you could also write L{e^at.g(t)} = G(s - a)? If it is, it would seem IMO the better way, in that there would be no risk of confusing the sign on the exponent of e.

Ensign_Cthulhu
Автор

Hi. By chance do you have .pdf, or some other file format, of the table you show near the beginning of the video?

doma
Автор

thanks for the video
 really helped me to understand

brothermcqueen
Автор

The formula is for sin at I didn't understand why you havent't taken the value of a=-1 ??

saumyayadav
Автор

thanks but could i just use integration by parts?

UnknownUserunknown
Автор

first of all what is shifting? ?? practical use of first shifting theorem

selvams