LeetCode 1929 Concatenation of Array Solution in Python | Easy Interview Problem Tutorial

Solve LeetCode 1929 "Concatenation of Array" in Python with this beginner-friendly tutorial! This easy problem asks you to create a new array by concatenating the input array with itself. We’ll use a simple one-liner `nums + nums` to solve cases like `[1, 2, 1]` (output: `[1, 2, 1, 1, 2, 1]`). Perfect for coding interview prep, Python learners, or anyone tackling LeetCode array challenges with straightforward solutions!

🔍 **What You'll Learn:**
- Understanding the Concatenation of Array problem
- Using Python’s list concatenation with `+`
- Creating a new array without modifying the original
- Testing with LeetCode test cases

💻 **Code Used in This Video:**
class Solution:
def getConcatenation(self, nums):
# Type: List[int]
# rtype: List[int]
return nums + nums # Concatenate the array with itself

# Test cases
nums1 = [1, 2, 1]
print(Solution().getConcatenation(nums1)) # Output: [1, 2, 1, 1, 2, 1]

nums2 = [1, 3, 2, 1]
print(Solution().getConcatenation(nums2)) # Output: [1, 3, 2, 1, 1, 3, 2, 1]

🌟 **Why Solve LeetCode 1929?**
This problem tests basic array manipulation—a fundamental skill for coding interviews at top tech companies! We’ll break down how `nums + nums` creates a new array by concatenating the input with itself, meeting constraints (arrays up to 10^3 elements). It’s a great starting point for beginners to learn list operations in Python—perfect for interview prep or Python practice!

📚 **Who’s This For?**
- Python beginners tackling LeetCode
- Coders prepping for tech interviews
- LeetCode enthusiasts solving easy problems

👍 Like, subscribe, and comment: What LeetCode problem should we solve next? Next up: LeetCode 1 Two Sum—stay tuned!

#PythonTutorial #LeetCode1929 #ConcatenationOfArray #CodingInterview #LearnPython

class Solution:
def getConcatenation(self, nums):
# Type: List[int]
# rtype: List[int]
# Concatenate the array with itself using +
return nums + nums

# Test cases
nums1 = [1, 2, 1]
print(Solution().getConcatenation(nums1)) # Output: [1, 2, 1, 1, 2, 1]

nums2 = [1, 3, 2, 1]
print(Solution().getConcatenation(nums2)) # Output: [1, 3, 2, 1, 1, 3, 2, 1]

nums3 = []
print(Solution().getConcatenation(nums3)) # Output: [] (empty array case)