LeetCode 162: Find Peak Element | Binary Search in JavaScript

In this video, I solve LeetCode 162: Find Peak Element using an optimized binary search approach in JavaScript.

The goal is to find any peak — an element that’s strictly greater than its neighbors — in O(log n) time. I walk through the binary search logic that checks neighbors to decide whether to go left or right, and return a peak index when found.

This is a clever twist on binary search, and it’s a favorite in technical interviews for testing algorithmic thinking beyond sorted arrays.

What You’ll Learn:
✅ How to apply binary search to unsorted problems
✅ What makes an element a “peak”
✅ Edge case handling in binary search
✅ Time and space complexity breakdown

Chapters:
0:00 - Problem Overview
1:25 - Explaining Solution
4:27 - Code Solution

💬 Want a follow-up for 2D peak finding (LeetCode 1901)? Let me know in the comments!

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