NCERT Chapter-01, Example 1.13 Solution, Physics Class 12th, Lecture 5.7

This video is made for the benefit of Class 12th students so that that they can understand Physics in easy and simple language.
In this video, a numerical (NCERT Example 1.13) based on Gauss law is discussed. We will discuss all the examples of NCERT with their corresponding topics and then will discuss the numerical exercise questions after the completion of each chapter. Assignments with MCQs, Fill in the Blanks, VSA etc will be provided as a link in the subscription at the completion of chapter or just before that.
Also the handwritten notes will be provided as a pdf link at the completion of each chapter.

Thank you

[AnuragSharma-nits]

Thank You Sir, Excellent Explanation ❤️

[smileshorts]

Aap se padhne ke baad questions ka concept clear ho jata hai

[SantoshYadav-qbqv]

Keep going, way of explaining is excellent

[xblakshrastogi]

Thank you sor you really did a grea job at explaining this example it really helped me a lot as I was not able to fully understand the solution of this example from the ncert. Thonks

[monachoubey]

These are so helpful sir ek ek cheez samjh aa jaati hai aapke padhane se
Thank you sir 🙏🏻😊

[vijayalakshmik]

Sir i have a doubt why we volume charge density why we cannot take surface charge density?

[mohdkamran]

Sir density nikalte time kuch charge nucleous ka bhi to hoga to sirf -ze kyu liya

[yogeshkumarsharma]

Sir, we take area of Gaussian surface as 4(pie)r^2.
Gaussian Surface is spherical so it must be 4/3(pie)r^3.
Please clear my doubt.