JEE: Newton’s Laws of Motion L4 | Constrained Motion | Unacademy JEE | JEE Physics | Namo Kaul

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Unacademy JEE | JEE 2022 | JEE Mains 2022 | JEE Advanced 2022 | Physics | IIT JEE Physics | JEE Physics | NEET Physics | Class 11 | Class 11 Physics | Newton’s Laws of Motion | Newton’s Laws of Motion Unacademy | Newton’s Laws of Motion Class 11 | Newton’s Laws of Motion In Hindi | Constrained Motion

Unacademy JEE brings you yet another JEE Physics session to prepare you for JEE Mains and JEE advanced. In this session, Namo Sir will be discussing JEE important topic "Constrained Motion from Newton’s Laws of Motion”, he will cover the basic concepts of the chapter and some special tricks to remember the concepts and solve questions. Watch this video to know all about "Constrained Motion from Newton’s Laws of Motion”.

Unacademy JEE is a free YouTube channel to help JEE aspirants in their preparation for JEE Mains and Advance 2022. The channel will guide you in making a strategy to decode the JEE question paper, revise every detail of all the subjects, and make a study plan that will help you prepare with confidence. Our Unacademy experts are committed to giving the best guidance for JEE 2022 preparations by analyzing the crucial needs of the students who want to crack the entrance exam and get through IIT JEE.

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Namo Sir is a great mentor and Physics lover and has been awarded for Best Teaching and Pedagogy at National T’CON 2018. In this IIT JEE Physics Live Online Class, Namo sir will touch upon the introduction, important questions, analysis, and strategy for "Constrained Motion from Newton’s Laws of Motion”. He is a passionate teacher and has helped many students crack IIT JEE. During the LIVE online classes, he keeps sharing his personal experiences with students preparing for IIT JEE 2022 to relate with them. This also helps the students get acquainted with the IIT JEE exam and make a study plan and strategy that will help them crack IIT JEE mains and advance in 2022.

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Use Special Code: "NAMOLIVE" (To avail Maximum DISCOUNT)

UnacademyJEE
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my first physice teacher jo physics ko easy bana diye hai killer visualization se sir thank you so much sir unacademy is best

amrishgautam
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Really sir pura din samajh nhi aaya jab aapka lecture dekha to samajh AA gya thanks 🙏🙏 sir

RaviVerma-ivsu
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i have a doubt, in the alternative of the second last q of lecture, pulley at block A was a movable pulley, then how through we passed the velocity as sir u told in last q we can travel through only fixed pulllet

speedstudying
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56:58 .. the reaction is just epic ... LOL.. xD xD

Traders_Paradise
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Sir what is the daily life usage of these pulley problems?

diprni
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Didn't like Namo sir before. After this lecture, respect.

sameerbisht
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pehle Jo quality education ka constrained tha vo UDAAN team me hata diya❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤love you team UDAAN ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

styfun
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Agar YouTube se koi achha lecture hai physics ka bo hai namo kaul sir 😘
Love you sir 😘😘 free mein itne achhe lectureship 😘😘

rudrashree
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I love reality because of Physics and I love physics because of you

arghyadandapat
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Thabkyou so much sir phele mai aapko bilkul bhi pasand nhi karta thaa but ab aapka fan hu sir

kirtanmalviya
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Sir at 12.55 you are wrong. If we consider falling block's velocity V' and ring's velocity as V. Then by string constraint as it is inextensible Vcos$ = V', where $ is angle of inclination of string making with ground at a particular instant of time.

Then for getting acceleration relationship we have to differentiate the above relationship of velocities. And for getting relationship of displacement we have to integrate the above relationship of velocities.

So it is not a' = acos$. It also depends on rate of change of $ with respect to time.

Thank you. I hope it will help many students. 😇

itzzkundan
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Thankyou so much sir for this wonderful lecture

suryanshchandel
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Constrained motion was tough but your teaching made it easy

mathenthusiast
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Love you Namo Sir....u made my physics miracle I love the way of ur teaching u r really awesome

Cooperativesaga
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How the velocity of each point on the string is same, the speed should be same and the direction is different

SanjayGupta-egbw
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Sir mujhe kinematics 2d ki notes chahiye bo kaha milegi

PayalRaj-gqpo
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Es tension ke padka mare tension jaada ho rhe hai 😱😱😱

chinjoo