Question 3 - Exercise 6.5 | Class 10 | Chapter 6 | Triangles | NCERT Maths | CBSE (Old Book)

00:00 Question explained
00:25 Which theorem will be used to solve it
00:55 Part 1 - Solution
04:24 How to backtrack to solve quickly
05:24 Part 3 - Solution
07:37 Part 2 - Solution
09:59 Part 2 - Alternate approach

Question 3, Exercise 6.5, Class 10, Chapter 6
In Fig. 6.53, ABD is a triangle right angled at A and AC ⊥ BD. Show that
(i) AB2 =BC.BD (ii) AC2 =BC.DC (iii) AD2=BD.CD

In this tutorial, you will find the explanation of the following:
Class: 10th
Chapter: 6, Triangles
Exercise : 6.5
Topic: Question 3
Textbook: NCERT

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