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MECHANICAL ENGINEERING LICENSE EXAM REVIEWER - Math Worded Age Problems - how old is the girl
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MECHANICAL ENGINEERING LICENSE EXAM REVIEWER - Math Worded Age Problems - how old is the girl
PROBLEM
A girl, is one-third as old as her brother and 8 years younger than her sister. The sum of their ages is 38 years. How old is the girl?
Given
girl is 1/3 as old as brother
girl is also 8 years younger than sister
38 sum of their ages
Unknown
how old is the girl
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SOLUTION
Let
g = age of girl now
b = age of the girl's brother now
s = age of the girl's sister now
equation 1
girl is 1/3 as old as brother
g = b/3
b = 3g
equation 2
girl is 8 years younger than sister
g = s - 8
s = g + 8
equation 3
38 sum of their ages
b + s + g = 38
substituting the values of b and s from equations 1 and 2 respectively, into equation 3
b + s + g = 38
but
b = 3g
s = g + 8
3g + (g + 8) + g = 38
3g + g + 8 + g = 38
5g = 38 - 8
5g = 30
g = 30/5
g = 6
(age of girl)
age of girl's brother
b = 3g
b = 3 x 6
b = 18
age of girl's sister
s = g + 8
s = 6 + 8
s = 14
checking:
sum of their ages 38
6 + 18 + 14 = 38
38 = 38
girl is 1/3 as old as brother
6 = 1/3 of 18
6 = 18/3
girl is 8 years younger than sister
14 - 6 = 8
*** Cheers ***
PROBLEM
A girl, is one-third as old as her brother and 8 years younger than her sister. The sum of their ages is 38 years. How old is the girl?
Given
girl is 1/3 as old as brother
girl is also 8 years younger than sister
38 sum of their ages
Unknown
how old is the girl
Subscribe like share
SOLUTION
Let
g = age of girl now
b = age of the girl's brother now
s = age of the girl's sister now
equation 1
girl is 1/3 as old as brother
g = b/3
b = 3g
equation 2
girl is 8 years younger than sister
g = s - 8
s = g + 8
equation 3
38 sum of their ages
b + s + g = 38
substituting the values of b and s from equations 1 and 2 respectively, into equation 3
b + s + g = 38
but
b = 3g
s = g + 8
3g + (g + 8) + g = 38
3g + g + 8 + g = 38
5g = 38 - 8
5g = 30
g = 30/5
g = 6
(age of girl)
age of girl's brother
b = 3g
b = 3 x 6
b = 18
age of girl's sister
s = g + 8
s = 6 + 8
s = 14
checking:
sum of their ages 38
6 + 18 + 14 = 38
38 = 38
girl is 1/3 as old as brother
6 = 1/3 of 18
6 = 18/3
girl is 8 years younger than sister
14 - 6 = 8
*** Cheers ***