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Merge Strings Alternately | Leetcode Python Solution | Step-by-Step Explanation #leetcode #coding

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In this video, we solve the Leetcode problem "Merge Strings Alternately" using Python in an efficient and easy-to-understand way.
The task is to merge two given strings by alternating characters from each string. If one string is longer, its remaining characters are appended to the end.
🔹 Step-by-Step Breakdown:
✅ Step 1: Define the Solution class
Leetcode requires the function to be inside a class named Solution.
✅ Step 2: Initialize Variables
Create an empty list merged to store merged characters.
Use two pointers i and j to iterate through word1 and word2.
Store the lengths of both strings in len1 and len2.
✅ Step 3: Merge Characters Alternately
Use a while loop to traverse both strings simultaneously.
Append one character from word1, then one from word2, and increment both pointers.
Repeat until the shorter string is fully processed.
✅ Step 4: Append Remaining Characters
✅ Step 5: Convert List to String
Use "".join(merged) to convert the list into a final merged string efficiently.
🛠️ Complexity Analysis:
⏳ Time Complexity: O(n + m) (where n and m are the lengths of word1 and word2).
💾 Space Complexity: O(n + m) (since we store the merged result in a list).
🔥 Don't forget to LIKE, SHARE & SUBSCRIBE for more coding solutions! 🚀
#leetcode #python #coding #datastructures #algorithms #programming #pythonforbeginners #leetcodeeasy #stringmanipulation #competitiveprogramming
The task is to merge two given strings by alternating characters from each string. If one string is longer, its remaining characters are appended to the end.
🔹 Step-by-Step Breakdown:
✅ Step 1: Define the Solution class
Leetcode requires the function to be inside a class named Solution.
✅ Step 2: Initialize Variables
Create an empty list merged to store merged characters.
Use two pointers i and j to iterate through word1 and word2.
Store the lengths of both strings in len1 and len2.
✅ Step 3: Merge Characters Alternately
Use a while loop to traverse both strings simultaneously.
Append one character from word1, then one from word2, and increment both pointers.
Repeat until the shorter string is fully processed.
✅ Step 4: Append Remaining Characters
✅ Step 5: Convert List to String
Use "".join(merged) to convert the list into a final merged string efficiently.
🛠️ Complexity Analysis:
⏳ Time Complexity: O(n + m) (where n and m are the lengths of word1 and word2).
💾 Space Complexity: O(n + m) (since we store the merged result in a list).
🔥 Don't forget to LIKE, SHARE & SUBSCRIBE for more coding solutions! 🚀
#leetcode #python #coding #datastructures #algorithms #programming #pythonforbeginners #leetcodeeasy #stringmanipulation #competitiveprogramming