Incrementation & decrementation operators in Java | Java Tutorials for freshers | Part 3

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Learn Increment & decrement operators conclusion in java, operators in Java, Java Tutorials for freshers.

In this episode the charismatic technical leader, Manjunath Aradhya Sir has taught Incrementation and Decrementation operators in Java. This is the ninth episode of the technical interview preparation video series. This video lecture is presented by one of the fastest growing technical training institutes in India i.e ABC for technology training. This episode is delivered by the visionary Founder and dynamic CEO of ABC for technology training Mr Manjunath Aradhya who has revolutionized the technical training domain using his 20+ years of teaching experience.

This is one of the most commonly asked interviews questions for freshers for software developer profile. The role of a software engineer is one of the respected jobs of the century. Every day, companies are looking out for more and more skilled software engineers and surveys show that there is only 4 to 5 percent of engineering graduates are qualified and skilled candidates to fill the roles.

This technical interview series of videos is recommended for all engineering graduates who aspire to become a software developer, CS, IS, EEE, ECE, TC engineering graduates, BCA, MCA, and MTech fresh graduates and all the programming faculties across universities.
This video lecture is helpful for all IT job aspirants and budding software developers. This episode is also a must watch for aspiring trainers and lecturers of programming languages across universities and software companies and learn the nitty-gritty of teaching. This is one of the most commonly asked interviews questions for freshers for software developer profile. This institute was envisioned by Mr Manjunath Aradhya to bridge the gap between engineering curriculum and software industry. So, let us dive deep into incrementation and decrementation operators in Java.

About the trainer: Mr Manjunath Aradhya, a technocrat by profession, a teacher by choice and an educationist by passion. Under his able leadership, ABC for Technology Training which is a National brand enabling the creation of thousands of careers annually in the IT Sector. He has also authored numerous hot selling engineering and other textbooks which are published by Pearson Education, an internationally acclaimed publication house headquartered in London. Other renowned international publishers such as Cengage Learning headquartered in Boston, United States, have published books authored by him.

ABC is an ISO 29990:2010 and ISO 9001:2008 certified organization with a 200+ member passionate team ENABLING CAREERS and contributing in its own way towards NATION BUILDING.

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Thank you very much sir for making a such awesome videos and making us understand java teaching style is fabulous sir feel very proud to be a part of ABC FOR TECHNOLOGY TRAINING you once again sir

sadhanapatil

class A{
public static void main(String args[ ]){
int a=5;
int b= a++ + ++a;
System.out.println("a: "a+" and "+"b : "+b);
}
}
out put:
a: 7 and b: 12

arunkumar__

b=a++ + ++a
use the technique
for post
use
incr
for pre
incr
use
a=5
b=a++ + ++a
b=5 + 7
b=12
ans is b=12

aamir

The answer to you question is a = 7 and b = 12

omrajpurkar

a = 5
b = a++ + ++a
b = 5 + 7
Ans: a = 7 and b = 12

punithbn

as the given expression is b=a++ + ++a.
Explaination:

1.So this is the expression which is first post incremented (a++) and then pre-incremented(++a) and final result b=is the sum of these two.
2.Assign the memory and values to a=5
3.As it is post incrementation, we should use it and then it's incremented.
4.As a result a value is incremented from a=5 to a=6. Resultant value is 6 here.
5.Then the second is pre- incrementation, we should increment the a value and then use it.
6.As a result a value is incremented from a=6 to a= 7 which is the final resultant value of a.
7.As mentioned above in point no.1 b= 5+7 =12
8.a=7, b=12.

anudeepakmishra

class Launch{
public static void main(String[] args){
int a=5;
int b= a++ + ++a;
System.out.print("a: "a + "and " +"b : "+b);
}
}
output:
-
a: 7 and b: 12

jwalapratap

After completion of Engineering, today I got this concept !! :)

sangamsingh

Sir we are Soo proud to be a part of ABC we like sooo much Sir we always refer ur institute for the upcoming graduates thanks a lot Sir

rayadurgamsravani

Nice explanation sir, Thankyou for uploading such videos

harishbonala

7
12
Awsome video sir....tq so much

kethineniashoknaidu

Thank u so much sir!! I saw so many video on this topic n i was all confused ..u explained it so well clean and clear ..plz keep up the good work 🖒🖒🖒

maliktarannum

Thank you so much for these videos sir its very helpful

prajnakamath

a=5;
b=a++ + ++a;
b=5 +7;
So b=12 and a= 7
Thank you sir😊

madhuranayak

int a=5;
int b=a++ + ++a;
output:
a=7
b=12

maruthibodapati

Intially taken the input a=5then apply the increment and decrement operators then a=7& b=12

deepu_keerthi

by doing this expression b = a++ + ++a . The out put is a = 7 and b = 12

sudhamaikotapati

After executing that program where expression has given
Int a=5;
Int b=a++ + ++a;
We get as result
a=7
b=12

jayprakashpankaj

a++ + ++a expression's output when the value of a=5 is 7 and 12 sir

jaitheerthanayaka

b=a++ + ++a
5+7
12
so a=7 and b=12

nagalakshmigannamanthi

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