Chemical Bonding Class 11 Chemistry | Fajan's Rule & Covalent Character | JEE Main 2024 | Rakhi Mam

45 Days Strategy to Crack JEE 2023 (Sure-Shot 200+ Marks) by Anshul Sir, Atiullah Sir & Rakhi Ma'am
Date: 20th Nov | Time: 11 AM

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Join this JEE live class to learn the concepts of Chemical Bonding from Class 11 Chemistry. In this Aakash BYJU’S AIM JEE 2024 Series, your favourite Chemistry expert, Rakhi Ma’am, explains Fajan's Rule & Covalent Character to boost your JEE Chemistry preparation for the JEE 2024 exams.

Further, Rakhi Ma’am discusses the following topics in this class:
1. Fajan's method
2. Polarising power in Chemistry
3. Polarising power and polarisability
4. Covalent character in ionic bond

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Moreover, Ma’am guides you on Chemical bonding Class 11 JEE questions and JEE Chemistry tips. If you have any doubts, ask in the live comment section below. Ma’am will solve your queries one by one.

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0:00 Chemical Bonding Class 11 Chemistry | Fajan's Rule & Covalent Character
3:56 Covalent Character in Ionic Compounds
12:42 Polarising power and polarisability
16:51 Fajan's Rule Explanation
21:01 1st Question
26:38 Order of Polarising Power
31:41 2nd Question
32:28 Polarization Directly Proportional to Charge on the Anion
36:11 3rd Question
36:43 4th Question
37:53 5th Question
46:03 6th Question
48:07 7th Question
55:39 Applications of Fajan's Rule
55:56 Variation in Melting Point
57:28 Melting Point directly Proportional to Lattice Energy
58:49 Melting Point inversely Proportional to Extent of Polarisation
1:00:06 Intensity of Color
1:00:46 Solubility in Water
1:03:19 Thermal Stability of Ionic Compounds

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[charvi]

Homework answer:
Q. Among the following options, the correct order(s) is/are:
a) Covalent character: CaCl₂ > SrCl₂ > BaCl₂ ✔
b) Thermal stability: PbF₄ > PbCl₄ > PbBr₄ ✔
c) Melting point: KF > KCl > KBr > KI ✔
d) Solubility in water: LiOH > NaOH > KOH > RbOH > CsOH ✖
Ans: In option (a) we have Cl₂ as a common anion. So, the covalent character will decrease with increase in the size of the cation, which is the case in the option. Hence, option (a) is correct.
In option (b) we have Pb as a common cation. So, as the interionic distance increases, thermal stablitiy will decrease. Hence, option (b) is correct.
In option (c) we know that as covalent character increases, melting point decreases. Hence, option (c) is correct.
In option (d) we have OH as a common multiatomic anion. So, the solubility in water increases with decrease in covalent character. Hence, option (d) is wrong.

Awesome session ma'am. Enjoyed a lot and learnt a lot at the same time. I still have a doubt in marking option (d) as wrong. But I think it is wrong. Thank you ma'am. 😊😊😊

[sakshisingh]

Can NEET Aspirants also watch this video for chemistry.

[aditipandey]

Awesome session mam...but doubt in question no.5 .I think high charges on ions means more electrostatic force so more will be ionic therefore option A will be right ...