Solving cos(2x) = cos(x) | A Trigonometric Equation

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cosx=cosθ <=> x = 2nπ +- θ, n € Z
So here:
2x=2nπ + x or
2x=2kπ - x so
x=2nπ or x=2kπ/3 where n, k € Z

Chrisoikmath_