SSC Maths practice| SSC CHSL 2024 Top 15 Geometry Questions 🔥

In this video, Shubham Sir will solve top 15 geometry questions of SSC CHSL 2024. Must watch video for SSC CGL 2024, SSC CHSL 2024 Tier-2, SSC CHSL 2025 and other future SSC exams.

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[ganeshchoudhary]

In Q5, don't need to find (3)^(1/4), as we have b^2 = 400 sqrt (3) = 400*1.7 = 680, which is larger than square of 26, So only possible correct option than will be option D. 26.32

[gorishankardsuthar]

Sir Last question ek baar check kro usme ∆HFB=~∆AFG

[ganeshchoudhary]

In Q6, Perimeter of triangle QSR is already given and equals to 27 + 18 + 36 = 81, So only 9 is possible in the denominator among given options. (In exam hall tips)

[mauryaclasses]

Sir question 2 sahi hai mera 15 aa raha hai ek bar similarities concept se check kar lijiye

[ar]

1:04:46 sir, ∆ hfb ~ ∆ afg correct. Please verify.

[dpkbisht]

Q2 is right 15 is the right answer
ADC~BAC.
(63/7)=(x/5)
√9=x/5
3×5=x
x=15 ans

[k.a.]

cgl pre live mocks jo abhi rbe site pr upload hue hai, test ke baad marks and solution kuch bhi show nai hote, overall result show nai horahe. ye problem aur bhi test me horahe hai. please solve this issue.

[anjuchaudhary]

question 2 similarity se ho jayega, area ka ratio 1:9, side ka ratio 1: 3 hoga, 1 ke correspondence 5 hai to 3 ke correspondence 15 hoga

[triumphssr]

बहुत बहुत आभार और बहुत बहुत धन्यवाद सर 🙏हम सभी विद्यार्थियों के लिए हमेशा तत्पर रहते हो, और पूरी मदद करते...शुभम sir great teacher ❤❤❤❤❤❤❤

[arp]

Sir Second question seems wrong if we consider the rules of Right angle property.
But answer is gettable using similarity property

[ashking]

Sir In the last question ∆hfb and afg∆ can be congruent ? cause If F, D is joined then it gives FG = FH and AG = HB ... 1:05:44

[ajoynandi]

Sir, Q.2 me hum aisa kar skte hai kya? ki area of ABC :area of ACD =63:7 to inka side ka ratio hoga 3√7:√7.
Dono similar triangle ka hypotenuse ka ratio(BC:AC)= x/5
therefore, x/5=3√7/√7
so, x(BC)= 15

[ashishkumarupadhyay]

Thank u sir for your videos and hard work

[erenackerman]

In △ ABC, P is a point on AB such that PB : AP = 3: 4 and PQ is parallel to AC. If AR and QS are perpendicular to PC and QS = 9 cm, what is the length (in cm) of AR?

△ABC में, P, AB पर एक बिंदु है जैसे कि PB: AP = 3 : 4 और PQ AC के समानांतर है। यदि AR और QS, PC के लंबवत हैं और QS = 9 सेमी है, तो AR की लंबाई (सेमी में) क्या है?

[ShikhaSingh-fmrg]

Q 7 sir Issey bhi option se tick kar saketa hai perimeter of SQR is 81 so denominator me multiple of 9 only one option

[SubhamayRaha-wnfz]

Q5. b = ✓400√3 = 20√3= 20*√1.73 = 20*✓173/100= 20*13/10=26 se thoda sa jada hga, as 173>169.

[suvodipkundu]

Q 15. IIIrd option you consider two wrong triangles. The triangles will be AFG and BFH.

[saimanikumar]

Sir please allow the option to attempt live mocks which has already completed, for those who has not attempted.( please extend previous mock available for one more week sir )

[vamsikrishnakolagatla]

provide telegram group for students discussion if any