A particle is moving in a verticalcircle such that the tensionin the string at the topmost point

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A particle is moving in a verticalcircle such that the tensionin the string at the topmost point B is zero.Theaccelerationof theparticle at point A is `(g=10m//s^(2))`
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How Va^2 = 9g^2 because Va = 3gr sir r^2/r

NiranjanGuptaSVJC