add two binary numbers in java | java tutorial for beginners

Write a Java program to add two binary numbers
#add #binary #number

[clarencecho]

WHAT, bro thank you so much I been studying one code to add binary numbers and it so complicated compare to yours.

[xelgringox]

Thanks for posting this. It was very helpful and not as complicated as other videos I had previously viewed.

[cr]

This was simplified and very helpful. Good teacher!!!

[ishan]

Very well explained my guy, and your speech is worth listening to for hours😅😂

[sherrycomm]

what is the function of parseint and tobinarystring? plz tell

[shunmugarajan]

What happen if we enter decimal number it will check "it is binary or not" OR is throw error

[tanvigupta]

Instead of parseint can we directly input in long data type?

[Ritik-ioof]

cant we do this code without the use of the wrapper class

[robokop]

how about this 102.96 to binary what it is code please help

[BusinessBookBite]

Sir why you are used 2
In the parseint

[iamjm_rishav]

Not that clear with the explanation, but the code is good.

[nizam-u-ddinpatoli]

BINARY ADDITION: Two decimal numbers are accepted as input and are
automatically converted into binary numbers and are added.

[spenceremmanuel]

Your method is very simplified man. Thanks!! Mine actually sucks

import java.util.Scanner;

public class Main<remainder> {
public static void main(String[] args) {
long binary1, binary2;
int i = 0;
int remainder = 0;
int sum[] = new int[20];
Scanner pot = new Scanner(System.in);

System.out.println("Print first binary number");
binary1 = pot.nextLong();

System.out.println("Print second binary number");
binary2 = pot.nextLong();
while(binary1!=0 || binary2!=0){
sum[i++]=(int)((binary1 % 10 + binary2 % 10 + remainder) % 2);

remainder = (int)((binary1 % 10 + binary2 % 10 + remainder) / 2);
binary1 = binary1 / 10;
binary2 = binary2 / 10;

}

if (remainder != 0) {
sum[i++] = remainder;
}
--i;
System.out.print("Sum of two binary numbers: ");
while (i >= 0) {
System.out.print(sum[i--]);
}
System.out.print("\n");
}
}

[bhimeshbhim]

Why the Parameters passed (x, 2) and (y, 2).. explain plz

[any_farooqui]

Ye kha pr run krna plz tell me plzzz...