Dynamics - Static Friction Q45

45 A 4.0kg brick is sitting on a table. The coefficient of static friction between the surfaces is 0.45. If a 10 N horizontal force is applied to the brick, what will be the force of friction? * * Students type their answers here [This object is a pull tab] Answer F fr = μ s F N F N = mg F fr = μ s mg F fr = (0.45)(4 kg)(9.8 m-s 2 ) = 17.64 N F app-=-- td=---