By definition, the area of that triangle is 50% of the area of that square, no matter how you draw the triangle.
rangerstl
It’s more efficient to not do the math when taking the SAT
trumpetaceman
Keeping the base (bottom segment) the same... If I move the top point (apex) left or right (along to top of the square/rectangle), and visualize new triangles connecting that point to the endpoints of the base, it's easy to see that ALL triangles I make have the same area, because the bases and heights for all these triangles are the unchanged (A=bh/2). I move the apex to the upper-left corner of the box. We know cutting a rectangle along its diagonal cuts it into two congruent triangles with the same area. So, the original triangle has 1/2 the area of the square, or 50%. Done, without finding the areas of either figure.
timeonly
If only I had this channel when I was in school :/ you’re teaching skills are awesome!
detx
Area of the triangle is 1/2 height x base. (Height x base) is the square.
Should take one second to solve
Tammamtu
You could split it into a 5x5 square and a 1x6 rectangle along the line down from the peak of the shaded triangle and set that both the squares are divided in half
yashasvik
Bro, you made this way harder than it has to be, since by definition its 1/2 x b x h for triangles and this IS a triangle (with obviously the same b and h), then its obviously 50%
andreaspatsalides
It's easier if thinking that moving the point at the top to one of the corners (you can do that because it's in a parallel line and it will always be the same area) the hypotenuse would be a diagonal of the square, so it would be 50%
ivanmedina
You can solve this visually. Just move the top of the shaded area slightly right and you have your answer. If your pressed for time…
donaldphillips
If you separate the square in two rectangles by the height of the triangle you can't see two half rectangles in those shapes
manipakravan
Just so people know, typically A = 1/2(B)(H) only works on a RIGHT Triangle it only worked on this triangle because it was inscribed within a square. However, If instead the non-right triangle was inscribed within a rectangle or any other shape other than a square you would calculate the wrong area!!
PS. The Correct way to solve a problem like this to be safe is to break up the triangle into small RIGHT triangle and add up the areas
madramon
Any triangle that touches two adjacent corners of a square and the opposite edge takes up 50%
whirled_peas
Just Mark two rectangles that arę literaly cut on half
JinKazamassj
simpler way to understand this is turn the box into a 1/6 and a 5/6 its half of the 1/6 and half of the 5/6 so the answer would be 50%
hasamanda
In case you are wondering why it is b . h
b stands for breast
h stands for holder
sunrevolver
One line and you can see it’s 50% on both meaning it’s 50%.
Math is so dumb sometimes-always asking for intermediate calculations :😢😂
rasmus
Basically it’s two triangles each covering half of two rectangles.
harstoft
I saw that by looking at it haha
There are two shapes cut in half
warpedworks
Or you can just see 50% of 5x6 and 50% 1x6
artemykuznetsov
Triangle and the quadrilateral with same base and between same parallels shallposses 50% area of quadrilateral.
