Python Programming Questions for Interview | Python Interview Questions and Answers For Frehsers

Python Programming Questions for Interview | Python Interview Questions and Answers For Frehsers
This video is part of Python Interview Questions and Answers. In this video, I have explained 3 important logical coding questions in python. Let's understand...

1) Python Interview Questions and Answers
2) Logical Questions in Python

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[anmolyadav]

***Another method to solve 3rd Problem (without creating another list)***
str1='a, b, b, c, c, c, d, d, e, a'
visited=[ ]
for char in str1:
if char not in visited and char!=", ":
print(f"{char}:{str1.count(char)}", end=", ")
visited.append(char)

Output: a:2, b:2, c:3, d:2, e:1,

Thankyou so much dude, Loved your teaching style man :)

[IQ_reviews]

Reversed list of string with different method

1) using inbuilt reversed function.

Str1 =[ "sky is blue"]
S2 =" ".join( reversed(Str1))
Print(S2)

2) using slicing method .
Str1 =[ "sky is blue"]
Print(Str1[::-1].split())

3) using while loops

Str1 =[ " sky is blue"]
S2 = Str1.split()
I=0
S3=" "
While i >0:
S3+=S2[i]
i-=1
Print(S3)

4)

Str1 =[ "sky is blue"]
S2 = Str1.split()
Print(S2[::-1])


5) using for loops

Str1 =[ "sky is blue"]

S2=" "
For i in Str1[::-1].split():
S2+=I
Print(S2)

[Rising_night_]

Bhaiya I am your biggest fan Love from jharkhand dhanbad ❤️

[cchandrikareddy]

Wow
Nice explanation very helpful video✨thanks🙂

[tyagishiva]

mystr="a, a, a, b, b, c, c, c"
b=""
e={}
a=mystr.split(', ')
for i in a:
if(i.isalpha()):
if(i not in b):
b=b+i#'a'+''='a'
d=a.count(i)
e.setdefault(b, d)
b=''
print(e)

[bidhanry]

for reversing just simply we can do it in one line -
print(' '.join(str1.split(' ')[::-1]))

[khetrabasitechvideo]

Sir itna achha content ❤️ Dil khus ho gaya

[khetrabasitechvideo]

Sir u deserve more subscriber... YouTube Mee dhund loo itna achha he koi v python ko samajhaya nahi

[IQ_reviews]

L=[a, a, a, b, b, c, c, c]
D=dict()
For i in L:
If I not in D:
D[I]=1
Else:
D[I]+=1
Print(D)

[vijendrachauhan]

Very well explained, it was really helpful. Expecting many more videos from u related to python interview questions

[meikamandoliini]

SoltoQ2:
input = [1, 2, 2, 3, 3, 4, 5, 5, 5, 6, 6]
store = {}
for obj in input:
if obj in store.keys():
store[obj] += 1
else:
store[obj] = 1

returnable = []
for key in store.keys():
if store[key] == 1:
returnable.append(key)

print(returnable)

[naguk]

Another way to do the 3rd problem is by importing Counter from collections module. the output will appear in a set
from collections import Counter
mystr = "a, a, a, b, c, b, b, c, c, c"
mylist= mystr.split(', ')
print(Counter(mylist))

output: Counter({'c': 4, 'a': 3, 'b': 3})
​

[RahulVerma-mqpr]

“Sir, this playlist containing 352 videos combines multiple playlists. Should I watch this playlist or follow each playlist separately?”

[meikamandoliini]

SoltoQ3:
input = "a, a, a, b, b, c, c, c"
input = input.split(", ")
store = {}
for obj in input:
if obj in store.keys():
store[obj] += 1
else:
store[obj] = 1

returnable = []
for key in store.keys():


print(", ".join(returnable))

[vaibhavverma]

list = [1, 2, 2, 3, 3, 4, 5, 5, 6, 6]

l = []
for li in list:
if list.count(li) == 1:
l.append(li)
print(l)

[meikamandoliini]

SoltoQ1:
input = "Sky is blue"
if input[-1] == ".":
input = input[0:-1]

l = input[0]
input = input.replace(l, l.lower())
input = input.split(" ")
input.reverse()
print(" ".join(input))

[arindampadhy]

good explanation, if possible make more videos like this.

[arun]

To solve 3rd problem in one line using dict comprehension.
my_str = "a, a, a, b, b, c, c, c"
d= {i:my_str.count(i) for i in my_str if i != ', '}

[systemsinfo]

print(f"\"{str2}\" ")

Output: "blue is sky"

[priyanshugupta]

Ek number bhai mst video tha biginer ke liye