JEE Physics: Semiconductors JEE Mains | JEE Sprint 2020 | Suri Sir | JEE Main 2020 | Vedantu JEE

Thinking about Semiconductors JEE Mains? JEE Physics - JEE Main 2020 (IIT JEE 2020). Today's JEE Sprint 2020 session is about Semiconductor IIT JEE (JEE Main 2020 Physics). Semiconductors JEE | Semiconductor for JEE Mains | Semiconductor JEE Main Questions | Semiconductor Questions for JEE Mains | Semiconductor IIT JEE Questions | Semiconductor Vedantu | Semiconductor Class 12 | JEE Main Physics | IIT JEE Physics | Vedantu JEE. Let's crack IIT JEE Physics by knowing the Semiconductors JEE Mains by Suri Sir. Learn more about Semiconductor for JEE Mains in IIT JEE Physics LIVE & Solve your doubts only at Vedantu JEE. Let's learn JEE Main Physics and crack JEE Mains 2020 at ease. Here we will cover all the Semiconductor jee main questions, shortcuts and tricks to make you understand the Semiconductor IIT JEE better.

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Thanks for watching this JEE Sprint 2020 session on Semiconductors JEE Mains 2020 (IIT JEE Physics) by Suri Sir. Hope you have enjoyed and learned more about Semiconductor JEE Main Questions / Semiconductors JEE Mains for JEE Main 2020 exam.

[ashokkumarshukla]

Perfectly understand.the.concepts but in que, 7 the ans would be 11.5 because silicon has 0.7v and hence I=(3-0.7)/200 =11.5

[shubhamsain]

There was an attack on Indian institue of science in 2005
Le suri sir:
The year when i appeard for Jee😉

[samsungsingh]

Silicon has 0.7V voltage so the ans is 11.7 is ans

[Madmaxkkb]

21:40 answer c is correct (the potential barrier for silicon is 0.7 therefore net emf = 3-0.7 = 2.3
I = 2.3/200
= 11.5mA )

[himanshu]

Answer to the HW is C (AB^—)
The session was GOOOOD and inspires NOT to LEAVE semiconductors for JEE..😊😁😎

[codebros]

But sir in the silicon diode question you have to subtract the potential barrier of silicon diode which is 0.7V so the net emf becomes 2.3 V and the current in the circuit will be 11.5mA
And i have also checked it from the solution of jee 2018 paper

[protoydebroy]

Answer of that silcon diode ques. will be 11.5 mA because si-diode has regular volt. of 0.7V so current I=3-0.7/200=2.3/200=11.5mA

[TANUJKUMARPandey]

last question answer is option C also Q.7 answer should be 11.5 since its not given that diode is ideal, drop across si diode is taken to be 0.7 volt.

[AjaySingh-idlh]

Ans.(C) ... AWESOME TEACHING GREAT SIR😍🤘

[HarshaVardhan-xxxq]

When they gave silicon diode we have to give breakdown voltage of 0.7 voltage so answer isn't 15
I also checked the previous years solutions

[HariKrishna-tnmq]

Suri sir!!
You are amazing..
Making toughest topics the easiest!!!🤟👏👏

[vemulakondavenky]

Jee 2018 question wrongly solved it's giving answer 11.5 .... Since it's connected to silicon diode it's resistance 0.7

[ridanizam]

In the first question, option d is also correct .. if we rearrange, simplify and try bringing α in the numerator we get the result

[sakshiiiii]

Answer of 7th question of 2018 is
I = 3 - 0.7 / 200
= 11.5 mA

[samratsannigrahi]

21:49 time ka answer c hoga because of Vsi =.7 volt .

[vaishnavicas]

In my perspective, Suri sir is a superman🦸🦸🦸 and I thought I should have ever seen him before because it's already so much late. I would suggest all my friends to see his videos. This is the first video which said to me that physics also is a easy subject. Thank you so much Suri sir🙏🙏🙏

[harshmishra]

Sir the soln of question at 20:12 is wrong answer is 11.5 mA please check

[kingdragon]

20.56 ans is C bause we will consider silicon as .7v .

[shreyanshkumar]

Answer of HWQ is option (C) [AB']

[KSHIVA-lklg]

the barrier potential of silicon diode is 0.7V. so the correct answer is 11.5A