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LeetCode 567 :Permutation in string - Explained + Java solution
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In this video, we solve the Permutation in String problem from LeetCode. Given two strings s1 and s2, the task is to determine if s2 contains a permutation of s1. We use the sliding window technique combined with frequency counting to efficiently check for any permutation of s1 in s2. Watch the complete explanation and see how to implement this solution in Java.
🔹 Problem:
You are given two strings s1 and s2. We need to return true if one of s1's permutations is a substring of s2, otherwise return false. This problem is a variation of the "Find All Anagrams" problem.
🔹 Solution Approach:
Sliding window technique to traverse through s2.
Character frequency maps to keep track of the current window in s2 and compare it to s1.
🔹 Time Complexity: O(n), where n is the length of s2.
🔹 Space Complexity: O(1), using a constant space for frequency maps.
If you're looking to master LeetCode-style problems or want to sharpen your coding skills, this video will guide you through step by step!
🔔 Don't forget to like, comment, and subscribe for more coding solutions!
🔹 Problem:
You are given two strings s1 and s2. We need to return true if one of s1's permutations is a substring of s2, otherwise return false. This problem is a variation of the "Find All Anagrams" problem.
🔹 Solution Approach:
Sliding window technique to traverse through s2.
Character frequency maps to keep track of the current window in s2 and compare it to s1.
🔹 Time Complexity: O(n), where n is the length of s2.
🔹 Space Complexity: O(1), using a constant space for frequency maps.
If you're looking to master LeetCode-style problems or want to sharpen your coding skills, this video will guide you through step by step!
🔔 Don't forget to like, comment, and subscribe for more coding solutions!