UPSC Mathematics Optional (in Hindi) | Linear Algebra | Lecture 44

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Acknowledgements & References (Booklist):

PAPER – I

1. Linear Algebra

2. Calculus

3. Analytic Geometry

4. Ordinary Differential Equations

5. Dynamics & Statics

6. Vector Analysis

PAPER – II

1. Modern Algebra

2. Real Analysis

3. Complex Analysis

4. Linear Programming

5. Partial Differential Equations

6. Numerical Analysis & Computer Programming
Computer Programming – Exademy Class Notes

7. Mechanics & Fluid Dynamics

Non-Programmable Scientific Calculator Mandatory for UPSC Mathematics Exam

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[souravbera]

Sir,
u= (2, 4, -8) v=(3, 6, -12)
from components of u and v we get,
v/u:
(3/2) = (6/4) = (-12/-8)
since, u and v are linearly dependent .
thank you sir😊

[divyalodha]

sir 44 : 34 par jo ques h uska c option me linearly dependent hoga kyu ki multiple h u 2 ka and v 3 ka

[mathswithqaisermobin]

Sir @34:07, the value of z should be 2b -c -a
By the way, your lecture is really helpful.

[prashantsingh]

Sir at 33:36, i think so z = 2b-a-c because equation after echelon form would be, -z = (a-2b+c) instead z = (a-2b+c) Pls correct me if i am wrong ?

[ajatshatru]

Sir at 57:40 The fourth row is coming out as a non-zero row (with -1 in C4; using other row operations) thus the given vectors will form the basis of R^4.
Pls. Correct I'm wrong...

[ranjanshil]

@ 1:09:15 sir R2 me to pairs of elements rahta fir {(1, -1, 0), (0, 1, -1)} basis kaise ban

[sirishp]

at 1:09:10 Sir, you are saying that it can form basis in R2 but in R2 (2 tuple) then any vector should be of the form (a, b) right? but here you are mentioning in the form (a, b, c) . Please clarify

[keshavkeshu]

Sir...51:19 pe (0, 0, 15) ki jagah (0, 0, 5) ayega..please chek

[FALLDAMAGE-kw]

sir at 43:43, i think the third equation will ne LD. because 3*u = 2*v. there u can be written as a scalar multiplication of v.

[ramsain]

Sir please ek request h Sir please phle paper 1 ko pura complete usme jese linear algebra ko complete krwa dijiye phir paper 1 ke second part jese dynamics and statics and so on i hope meri request aap ko achi lage thank you for valuable section 😊

[manojmeena]

Dear sir, thank you so much for making linear algebra easy . During theory lectures, it required patience but this lecture of questions really brought so much confidence . 🙏🏻🙏🏻🙏🏻

[ramenglish]

Z=-a+2b-c
Y=3a-7b+4c
X=-a+9b-3c
AA Raha hai sir mera

[krunaldalwadi]

"Agar shortcut use karoge to marks bhi katenge aur kuch aur bhi" - Sir, your class is filled with humor and we never feel how time passes by learning mathematics 😊😊😊

[vsta]

Sir what about concept of eigen values, eigen vector and quadratic form of matrices

[parth]

At 44:42, option c is linearly dependent :)

[gauravgehlot]

your answer is correct sir except for -a in z
x = -a+5b-3c
y = 3a-7b+4c
z = -a+2b-c

[anshul]

Sir at 32:48 the correct answer of the question is
X= -3a+5b+3c
Y= 3a-7b+4c
Z= -a+2b-c

[itsadil]

sir 57:51, last row non zero aara, i used the different row operation .please clarify sir .

[tanmeetsingh]

Sir, at lecture timing 51:21 third Basis vector of R^3 will be (0, 0, 5)

[onsirclasses]

#33:35 ans---- x=(-a+5b-3c), y=(3a-7b+4c), z=(2b-a-c) 👍👍👍