Graphing a Rational Function - Example 3

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  1. patrickJMT
  2. math
  3. algebra
  4. graph
  5. rational
  6. function
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Комментарии
Автор

THANK YOU SO MUCH! I never understood how to know whether it's a vertical asymptote or a hole, and you made me get it in like 5 seconds! this is so easy, why can't my teacher explain it like this?!!!

BWithEmMarie
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@MrBIGmac562 because the limit exists at one of those points. 0/0 is not an asymptote.

patrickjmt
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you're my Savior!!! love this!!

yummy
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The vertical asymptotes occur when the denominator of a rational function is equal to 0. This means that you are dividing by 0, causing the graph to shoot off to negative or positive infinity. In this equation, the denominator is equal to x^2-9. Three and negative three make this equal to 0, meaning these are your vertical asymptotes

bennysmith
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¿Cómo grabas tus videos?, ¿Qué tipo de camara?

Gracias, y muy buenos videos.

CarlosAlbertoJulianSanchez
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just realized he's left handed. yeah!

Jakenbake
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I do not understand how do you know the way the function is going to behave without plotting values for x .

volg
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Thx for the help man! my exam final score is 50/50

jray
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I am sorry can you help me. What do you mean by a " hole in the graph? " BTW I love ur videos.

WWadventure
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how can I find the x and y intercept, assyptotes of this rational function y=x/x^2+x+1

fernandonavarro
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is there always a VA no matter what is the degree of the numerator and denominator?

alex
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hmm i thought the V.A was -6 not -3, confused on how that worked, will come back to this

ijustwannabeadrummer
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Why didn't you add a horizontal asymptote to the graph??? Please help!!! :/

SmokingSuns
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I'm still don't understand how to get " real except..." anyone can help me ?

dibbajohari