Part 27 Question 11.7 to 11.13 of Electricity | Electricity | CBSE

Example Question 11.7 to 11.13 of Electricity Class 10 NCERT Science Chapter 11 | Electricity | CBSE
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THROUGH THIS VIDEO YOU WILL LEARN :
Example 11.7 - An electric lamp, whose resistance is 20 Ω, and a conductor of 4 Ω resistance are connected to a 6 V battery (Fig. 11.9). Calculate (a) the total resistance of the circuit, (b) the current through the circuit, and (c) the potential difference across the electric lamp and conductor.
Example 11.8 -In the circuit diagram given in Fig. 11.10, suppose the resistors R1 , R2 and R3 have the values 5 Ω, 10 Ω, 30 Ω, respectively, which have been connected to a battery of 12 V. Calculate (a) the current through each resistor, (b) the total current in the circuit, and (c) the total circuit resistance.
Example 11.9 - If in Fig. 11.12, R1 = 10 Ω, R2 = 40 Ω, R3 = 30 Ω, R4 = 20 Ω, R5 = 60 Ω, and a 12 V battery is connected to the arrangement. Calculate (a) the total resistance in the circuit, and (b) the total current flowing in the circuit.
Example 11.10 -An electric iron consumes energy at a rate of 840 W when heating is at the maximum rate and 360 W when the heating is at the minimum. The voltage is 220 V. What are the current and the resistance in each case?
Example 11.11 -100 J of heat is produced each second in a 4 Ω resistance. Find the potential difference across the resistor.
Example 11.12 - An electric bulb is connected to a 220 V generator. The current is 0.50 A. What is the power of the bulb?
Example 11.13 - An electric refrigerator rated 400 W operates 8 hour/day. What is the cost of the energy to operate it for 30 days at Rs 3.00 per kW h?
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