Fundamental Theorem of Finite Abelian Groups, Proof 2

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Fundamental Theorem of Finite Abelian Groups, Proof 2
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mistake @5:23.. It is not "for all x in G", but it should be "for all x in <a>", the subgroup generated by the element of maximal order...

sahhaf
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After @7:30, it is ununderstandable... why |b|=p ? why |b^p| = |b|/p ?
---are these assumptions we will prove or disprove?
---are these facts that we should already know?
no clue.

sahhaf
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sir
why is that b^p belongs to <a>

parvezpatel
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In Lemma 2, @1:40 : He forgot to say that group G's order is assumed to be p^n, hence the n he used in the definition of K comes from there..

sahhaf
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it is very hard to follow... but it is very good!!

discipulusoperarios