Profit & Loss | Maths Online Classes | Class 7-ICSE | Part 1 | Swiflearn

"Profit & Loss | Profit | Loss | Profit Percent | Loss Percent

This Session is of LIVE Online Class of Profit & Loss of Class 7-CBSE Maths. In this session, Nitisha Ma'am will teach you Profit & Loss.The topics that are going to be covered in this session are :

Profit & Loss
Profit
Loss
Profit Percent
Loss Percent

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#Profit & Loss
#Profit
#Loss
#Profit Percent
#Loss Percent

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❖ Cost Price : The price at which an article is purchased is called as Cost Price.
❖ Selling Price : The price at which an article is sold is called as Selling Price.
❖ Profit : If the difference between the selling price and cost price is positive , then the
difference is called the Profit.
PROFIT = SELLING PRICE - COST PRICE
❖ Loss : If the difference between the selling price and cost price is negative , then the
difference is called the Loss.
LOSS = COST PRICE - SELLING PRICE
❖ Overhead Expenses : Usually a merchant has to nspend some money on freight , labour
or maintenance of the purchased articles . These extra expenditures are called Overhead

 EXAMPLE 1
Find the unknown values from the following :
1) C.P = Rs. 500.00 , S.P = Rs. 600.00 , Profit / Loss = ?
2) C.P = ? , S.P = Rs. 2390.00 , Profit = Rs. 120.50
SOLUTION : 1) we have ,C.P = Rs. 500.00 , S.P = Rs. 600.00,
Clearly , S.P C.P
So ,there will be profit is given by
Profit = S.P - C.P
= Rs. 600.00 - 500.00 = Rs. 100.00
Profit = Rs. 100.00
2) we have , S.P = Rs. 2390.00
We know that , Profit = S.P - C.P
C.P. = S.P. - Profit
= Rs. 2390.00 - 120.50 = Rs. 2269.50
Hence , C.P. = Rs. 2269.50
Short Notes
Class 6 ICSE

❖ Profit and Loss Percent : We cannot compare any profit directly . We can make a correct
comparision only if we know their profits for the same cost price .
Generally , the profit or loss is expressed as profirt % or loss % .
Profit % =
. .
Pr
C P
ofit
× 100 =
. .
. .
C P
S P −C P
× 100
Loss % =
C.P.
Loss
× 100 =
. .
. . . .
C P
C P − S P
× 100
 EXAMPLE 2.
Neha bought 1600 bananas at Rs. 3.75 per dozen . She sold 900 of them at 2 for Rs. 1 &
the remaining at 5 for RS. 2 . Find her gain or loss per cent .
SOLUTION : Cost of one dozen of bananas = Rs. 3.75
Cost of 1600 bananas = Rs .






×1600
12
3.75
= Rs.





 
12
375.00 16
= Rs. 500.00
Thus , C.P. of 1600 bananas = Rs. 500.0
Now the selling price of 900 bananas at thec rate of 2 of Rs. 1.00 =Rs.






2.00
900.00
= Rs. 450.00
The selling price of the remaining ( 1600 - 900 ) = 700
Bananas at the rate of 5 for Rs. 2 , = Rs.





 
5
2 700
= Rs. 280.00
S.P. of 1600 bananas = Rs. ( 450.00 + 280.00 ) = Rs. 730.00
Now , C.P. of 16000 bananas = Rs 500.00
And , S.P. of 1600 bananas = Rs. 730.00
Clearly , S.P. C.P.
So , there is a gain given by Gain = S.P. - C.P.
= Rs. ( 730.00 - 500.00 ) = Rs. 230.00
Hence , gain percent =






×100
C.P.
Gain
=






×100
500.
230
= 46 %

To download FREE Revision notes for Fundamental Unit of Life Class 7 CBSE Maths visit :

[jyoti]

I think u should first explain cost price n selling price n then give them some examples n formula to caculate profit n loss..it would be easier for them

[vs-cpch]

I want to apply for the job..but I'm tamil medium students can I get a chance?

[rupsaghosh]

should we need to explain all the 45 slides for demo 1 in 6 mins or I can explain maximum slides which can be explained in that time? please help.

[shreyasrivastava]

Today i had given my demo on this topic only