Practice Problem 4.9 Fundamental of Electric Circuits (Sadiku) 5th Ed Thevenin + Independent Source

Find the Thevenin equivalent circuit of the circuit in Fig. 4.34 to the
left of the terminals.
Answer: VTh 5.333 V, RTh 444.4 milliohm

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[whatsnew]

Sir, your videos are very helpful and your solved questions are very easy to understand.

[studybean]

thank you so much for solving all of the problems for this book, it really helps me in my subject

[fadyalazrak]

thanks a lot, Tomorrow I have an exam and I didn't understand this problem, thanks man

[Root]

I am so impressed by ur network solving skills

[louise]

Thank you so much. That was brilliant.

[مصطفىبخاري-مط]

thank you so much, your videos are very helpful,
but i have a question,
at 15:33 why did you assume that the current go to the rite?

[SayemTalukder_Ex-HinduAjayArya]

Do you have any video on Example 4.9 solved by Nodal analysis sir?

[wantwildworld]

Thanks for helping with our problems sir. Please sir I have a question, can we use the current source, I mean instead of using V=1v we use I=1A.
I'm not having my way using the current....

[marwansafwan]

Thanks
BTW which country are you from??

[learnwithjai]

Sir please solve practice problem 10.9 in Alexander Saiduku book 🙏🙏🙏🙏

[ishitaa]

Why have you taken that point grounded ?

[PubgG-hpwm]

why 1 voltage taken to calculate Rth ???

[jonahlang]

16:22 how come you can assume Vq is 1?

[randomppl]

Excuse me, can i ask why don't we use method like Problem 4.8 (previous video) when we want to find the Rth. I just confused

[ShahidKhan-djcg]

For Rth we turn off independent source but here you doesn't turn off why????

[bilalarisar]

Sir please solve the practice problem 14.2. Please sir

[c.cody.]

eh may I ask why is vq equal to 1v at 16:28?

[kanishhh]

Hey, calculating Vth by mesh analysis and using concept of supermesh as there is a dependent source between two meshes is giving wrong answer. Can you explain why we can't use that concept here??

[manveshdwivedi]

This is so slow
I can't tolerate

[khondokerolin]

thanks you sir....what's your facebook id, sir?