Surface Area of revolution about the y-axis of x^2]4 - lnx2

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In this video, I showed how to compute the surface area of revolution of a function about the y-axis. i explained how to choose the radius of revolution depending on what axis the revolution is about.
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I feel like the question should include the fact that the base of the solid is also bounded by the y-axis, since that is how you drew it but it's not obvious that thats the case from only the initial information given; perhaps something like "The base of a solid is given by the region bounded by the y-axis and the graph y = x²/4 - ln(x)/2 on the interval x∈[1, 2]. This region is then rotated about the y-axis to form the solid. Determine the surface area of this solid." Regardless, awesome question and great explanation

Samir-zbxk
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Thanks Sir for the excellent explanation.

surendrakverma
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Wouldn't the shape formed by rotation be more like a curved collar instead of a bowl?

RobG
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Hi sir one question why ds is square root of 1+f'(x)? is it the same for all the problem?If you have video about it i will make sure to watch ❤

anisa
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Lol 😂 We know all the x' s are greater than 1 for this problem. So, positive.

ThenSaidHeUntoThem
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This question is to be answered until 11:59 am, for those who have the last digit of their DNI 5: What is the letter you like the most among A, B, C, I, N, The m?

matheodaniloalvitreslopez
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Esta pregunta es para que me respondan hasta las 11:59 am, para los que tienen el último dígito de su DNI 5 : ¿Cuál es la letra que les gusta más entre la A, la B, la C, la I, la N, la M?

matheodaniloalvitreslopez
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professor bring some tough problem these are too easy

Harrykesh