Introduction to Functional Programming in Haskell: Episode 1- Lambda Calculus

In this lecture we'll be covering Lambda Calculus

[chachan]

Thank you so much! Best in-depth explanation of Lambda calculus on YouTube that I've found!

[AbdulZurghani]

so in the case of
\a(\b.abz) q r
gives -> qrz
the r is an argument for the \b and q is for \a ?
i understood the the first function takes first argument second that the second and so on.
is that correct ?

[NagaCharanMeda]

Hej @madgen videos, can you also share the presentation. Thanks