JEE Advanced 2020 Paper 2- Limits Problem

This video covers a highly challenging problem on Limits and gives a method to solve it in less than 2 minute with the help of graphs, which would otherwise take a very long time to solve. This is taken from recently held JEE Advanced 2020 Paper II question number 6 and the question is
The value of the limit limx→π/2 4√2(sin 3x + sin x)(2 sin 2x sin 3x/2 + cos5x/2) − (√2 + √2 cos 2x + cos3x/2) is _____
This video is suitable for the students aspiring for engineering entrance exam and is also suitable for CBSE, ISC, HSC, IB Board students and the students who have genuine interest in learning Calculus
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[krishnathawani]

We can get solution of previous year question anywhere....but the most important thing in previous year question is way of explaining it . Sir, u explained it very well.
Thanks😊