Moment of Inertia of a Composite Section_Problem 1

In this video, we will determine the #momentofinertia of a composite plane.
Watch the video, right till the end to have firm grasp on the concept.
#engineeringmechanics
#appliedmechanics
#fundamentalsofmechanicalengineering
#whatiscentroid
#whatiscenterofgravity
#whatiscentreofgravity
#centroid
#momentofinertiaofcompositeplane

[kjeevan]

I could have never passed my sem exam(bem)without this knowledge, thank u for this wonderful lecture

[abassmobolaji]

For the semi circle. It’s not meant to be 0.11*(4)^4. It should be pi over 8 then multiply be 4^4.

[brillamariyamsunny]

Sir ...I am very thankful to semester I studied the whole engineering graphics from ur suggested it to my really helped scored good marks semester ur engineering mechanics lectures are really helpful a lot sir

[johnfrancis]

for semi circle we can use (pi/8 x r^4) where r = 4 directly ... also for circle we can use(pi/4 x r^4) where r = 2 directly

[brhaneamha]

How did you get the semicircle MOI and Circle MOI
That semi circle
= (3.1415)4^4 /8 +ad^2
for that Circle
MOcm=pi*r^4/4+0=201.061

[pradnyakharade]

Sir you have literally helped me to infinity cz I was not knowing anything i.e. how to calculate it as I missed my mechanics lacture

But got a great social tutor.

[advaitharun]

Why didn't we calculate centroid for this question ?as we do for all until now

[DasariKartik]

For semi circle and quarter circle you have taken radius instead of diameter in your formula. Please correct it or else people get confuse. remaining good explanation

[polankirajulu]

Please tell me more about Moi of composite sections (about semicircle problems)

[shubhashyadav]

Sir, for the same figure how to find MOI about its centroidal x-axis?

[swatisahay]

how do we understand whether we have to take the x distance or y distance from the given line? like in the previous video we got the x component and the y component, we dont have to do that in this?

[ZainKhan-cysp]

sir the semicircle is in 3 4 quadarant and in 3 4 quadarant the y values is negative, then sir why you should not represent the y distance in (-) form

[julieanneamar]

Do you also know how to solve the polar and radius of gyration? And where is the y axis. Thank you

[saketpandey]

Thanks a lot sir this explanation helped me a lot in my CA.

[imtiaz]

Sir, in your previous videos (eg. I beam), the "y" value was (value of centroid "y" - y1/y2/y3) but in this video you directly took y1/y2/y3 value. I couldn't understand.

[arinzeanthony]

Please, I have a couple of questions, isn't Ix of a semicircle meant to be equal to Iy? what of quarter circles, if we were to find Ixx and Iyy when parrallel and perpendicular to a quarter circle, what values do we use?
Also, for semicircles, I know how they obtained that 0.393r^4 =(pi.r^4/8). But how did you get 0.11r^4?

[ntegral]

Sir, how did u get the 0.11 in IAB2? How to calculate? Plss help!

[sebtodd]

WHY IS IT THAT INDIAN GUYS ON YOUTUBE ARE BETTER TEACHERS/EXPLAINERS THAN ANY OF MY PROFS WITH PHD'S AT A TOP SCHOOL IN CANADA

[manishadhikari]

Smart way of teaching sir ..❤
It cleared my dbt

[shriramparab]

Sir, for semicircle how did you get that 0.11*(4)^4