we factor out 1/2 and multiply by 3/3, so nothing is really changing, note,
sin(3x)/(2x) = (3/2)* sin(3x)/(3x) and sin(3x)/(3x) -> 1, so you get (3/2)*1 = 3/2. In general, sin(ax)/(bx) -> a/b as x ->0, here a = 3, b = 2
TheMathSorcerer
I cant belif i finally watching stuff like this
taetaecooky
Here is how I did it:
I divided this by x/x so the lim as x --> 0 of sin3x/x/2x/x . This leaves you with sin3x/x/2 I then multiplied it by 3/3 which gives you 3/2 lim as x --> 0 sin3x/3x. This means it is 3/2 * 1 = 3/2
Hope this helps if you are still confused
chadbowman
It's very hard to understand ur solving 💀
Swifie-pk
The Sin and the x cancel out which gives us a result of 3/2
ACertainMan
Sir can squeeze theorem be applied here?
zeeshanahmed
what grade in your country can learn about lim?
ngoclinhphan
this is wrong when u multiply by 3/3 shouldn't it be 3sin3x/3x
raynier
Shouldn't it be 1/6, because you are multiplying the sin function by 1/3 to get the x in the denominator to 3x.
